Convert pound-force to pound foot/square second

Please provide values below to convert pound-force [lbf] to pound foot/square second [lb*ft/s^2], or Convert pound foot/square second to pound-force.




How to Convert Pound-Force to Pound Foot/square Second

1 lbf = 32.1740496090737 lb*ft/s^2

Example: convert 15 lbf to lb*ft/s^2:
15 lbf = 15 Γ— 32.1740496090737 lb*ft/s^2 = 482.610744136105 lb*ft/s^2


Pound-Force to Pound Foot/square Second Conversion Table

pound-force pound foot/square second

Pound-Force

Pound-force (lbf) is a unit of force in the imperial system, defined as the force required to accelerate a one-pound mass at a rate of 32.174 feet per second squared.

History/Origin

The pound-force originated from the British Imperial system and has been used historically in engineering and physics to quantify force, especially in the United States and the UK, before the widespread adoption of the SI system.

Current Use

Today, pound-force is primarily used in the United States and some other countries for engineering, manufacturing, and mechanical applications where imperial units are still prevalent, often in contexts like specifying engine torque or structural loads.


Pound Foot/square Second

The pound foot per square second (lb*ft/s^2) is a unit of force representing the force exerted by a one-pound mass accelerated at one foot per second squared.

History/Origin

This unit originated from the imperial system of units, primarily used in the United States, to quantify force based on the pound as a unit of mass and foot as a unit of distance, with seconds as the time unit. It is related to the pound-force (lbf) but includes a distance component, making it a derived unit in mechanics.

Current Use

The pound foot per square second is rarely used in modern practice; force is typically expressed in pound-force (lbf). When used, it appears in specific engineering contexts involving force calculations in imperial units, especially in classical mechanics and engineering analyses.