Convert pound-foot/hour to megajoule/second
Please provide values below to convert pound-foot/hour [lbf*ft/h] to megajoule/second [MJ/s], or Convert megajoule/second to pound-foot/hour.
How to Convert Pound-Foot/hour to Megajoule/second
1 lbf*ft/h = 3.76616e-10 MJ/s
Example: convert 15 lbf*ft/h to MJ/s:
15 lbf*ft/h = 15 × 3.76616e-10 MJ/s = 5.64924e-09 MJ/s
Pound-Foot/hour to Megajoule/second Conversion Table
| pound-foot/hour | megajoule/second |
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Pound-Foot/hour
Pound-foot per hour (lbf·ft/h) is a unit of power representing the amount of work done in foot-pounds per hour, commonly used in engineering to measure power output or consumption.
History/Origin
The pound-foot per hour originated from the imperial system of units, primarily used in the United States, to quantify power in mechanical and engineering contexts. Its usage has declined with the adoption of SI units but remains relevant in certain industries.
Current Use
Today, pound-foot per hour is primarily used in specific engineering fields, such as mechanical and aerospace engineering, for measuring power in systems where imperial units are standard. It is also used in historical data and legacy systems.
Megajoule/second
A megajoule per second (MJ/s) is a unit of power equivalent to one megajoule of energy transferred or converted per second, where 1 megajoule equals 1,000,000 joules.
History/Origin
The megajoule per second has been used in scientific and engineering contexts to quantify large-scale power, especially in fields like physics and energy systems, as a convenient unit for expressing high power levels. It is derived from the SI units of energy (joule) and time (second).
Current Use
Today, MJ/s is primarily used in scientific research, energy production, and engineering to describe high power outputs, such as in power plants, large-scale energy systems, and theoretical calculations involving energy transfer rates.